Enter the conditions at two points along a streamline and get the static pressure at the second point — with each energy term shown separately, so you can see where the pressure actually went.
Solve for P₂
Steady, incompressible, frictionless flow along one streamline.
Static pressure at point 2
=
| Term | kPa |
|---|---|
| P₁ — static pressure in | |
| ½ρ(v₁² − v₂²) — velocity change | |
| ρg(h₁ − h₂) — elevation change | |
| P₂ — static pressure out |
The equation
Bernoulli’s equation says that along a streamline, the sum of three energy terms stays constant:
Rearranged for the pressure at point 2, which is what this tool solves:
Read it as a budget. You start with P₁. Speeding the fluid up costs pressure. Lifting it costs pressure. Whatever is left is P₂.
The flow must be steady (not changing with time), incompressible (fine for liquids, and for gases below about Mach 0.3), frictionless (no viscous losses), and both points must lie on the same streamline.
Friction is the one that catches people out. In a long pipe, a partly closed valve, or anything with a sharp bend, the losses are not small and the real P₂ will be lower than this calculator says. The full article works through a real example and shows how far off you get.
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